1054331112129 has 4 divisors (see below), whose sum is σ = 1405774816176. Its totient is φ = 702887408084.

The previous prime is 1054331112049. The next prime is 1054331112137. The reversal of 1054331112129 is 9212111334501.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1054331112129 is a prime.

It is a super-2 number, since 2×1054331112129² (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1054331112129.

It is not an unprimeable number, because it can be changed into a prime (1054331112169) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 175721852019 + ... + 175721852024.

It is an arithmetic number, because the mean of its divisors is an integer number (351443704044).

Almost surely, 2^{1054331112129} is an apocalyptic number.

It is an amenable number.

1054331112129 is a deficient number, since it is larger than the sum of its proper divisors (351443704047).

1054331112129 is an equidigital number, since it uses as much as digits as its factorization.

1054331112129 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 351443704046.

The product of its (nonzero) digits is 6480, while the sum is 33.

The spelling of 1054331112129 in words is "one trillion, fifty-four billion, three hundred thirty-one million, one hundred twelve thousand, one hundred twenty-nine".