1054331112130 has 32 divisors (see below), whose sum is σ = 1901958153984. Its totient is φ = 420807869376.

The previous prime is 1054331112049. The next prime is 1054331112137. The reversal of 1054331112130 is 312111334501.

It is a super-2 number, since 2×1054331112130² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1054331112095 and 1054331112104.

It is not an unprimeable number, because it can be changed into a prime (1054331112137) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 28265052 + ... + 28302328.

It is an arithmetic number, because the mean of its divisors is an integer number (59436192312).

Almost surely, 2^{1054331112130} is an apocalyptic number.

1054331112130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1054331112130 is a deficient number, since it is larger than the sum of its proper divisors (847627041854).

1054331112130 is a wasteful number, since it uses less digits than its factorization.

1054331112130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43410.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 1054331112130 its reverse (312111334501), we get a palindrome (1366442446631).

The spelling of 1054331112130 in words is "one trillion, fifty-four billion, three hundred thirty-one million, one hundred twelve thousand, one hundred thirty".