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1055100000035 = 5239379791657
BaseRepresentation
bin11110101101010001101…
…11000101011100100011
310201212101201210102221002
433112220313011130203
5114241321100000120
62124412314422215
7136141235011364
oct17265067053443
93655351712832
101055100000035
11377513497504
1215059aa3196b
137865980a963
14390d2229b6b
151c6a3c17375
hexf5a8dc5723

1055100000035 has 16 divisors (see below), whose sum is σ = 1322578829376. Its totient is φ = 806519121408.

The previous prime is 1055099999869. The next prime is 1055100000043. The reversal of 1055100000035 is 5300000015501.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 1055100000035 - 210 = 1055099999011 is a prime.

It is a super-2 number, since 2×10551000000352 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1055099999962 and 1055100000016.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4788074 + ... + 5003583.

It is an arithmetic number, because the mean of its divisors is an integer number (82661176836).

Almost surely, 21055100000035 is an apocalyptic number.

1055100000035 is a deficient number, since it is larger than the sum of its proper divisors (267478829341).

1055100000035 is an equidigital number, since it uses as much as digits as its factorization.

1055100000035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9792622.

The product of its (nonzero) digits is 375, while the sum is 20.

Adding to 1055100000035 its reverse (5300000015501), we get a palindrome (6355100015536).

The spelling of 1055100000035 in words is "one trillion, fifty-five billion, one hundred million, thirty-five", and thus it is an aban number.

Divisors: 1 5 23 115 937 4685 21551 107755 9791657 48958285 225208111 1126040555 9174782609 45873913045 211020000007 1055100000035