Base | Representation |
---|---|
bin | 11110101101010001101… |
… | …11000101011100100011 |
3 | 10201212101201210102221002 |
4 | 33112220313011130203 |
5 | 114241321100000120 |
6 | 2124412314422215 |
7 | 136141235011364 |
oct | 17265067053443 |
9 | 3655351712832 |
10 | 1055100000035 |
11 | 377513497504 |
12 | 15059aa3196b |
13 | 7865980a963 |
14 | 390d2229b6b |
15 | 1c6a3c17375 |
hex | f5a8dc5723 |
1055100000035 has 16 divisors (see below), whose sum is σ = 1322578829376. Its totient is φ = 806519121408.
The previous prime is 1055099999869. The next prime is 1055100000043. The reversal of 1055100000035 is 5300000015501.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 1055100000035 - 210 = 1055099999011 is a prime.
It is a super-2 number, since 2×10551000000352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1055099999962 and 1055100000016.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4788074 + ... + 5003583.
It is an arithmetic number, because the mean of its divisors is an integer number (82661176836).
Almost surely, 21055100000035 is an apocalyptic number.
1055100000035 is a deficient number, since it is larger than the sum of its proper divisors (267478829341).
1055100000035 is an equidigital number, since it uses as much as digits as its factorization.
1055100000035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9792622.
The product of its (nonzero) digits is 375, while the sum is 20.
Adding to 1055100000035 its reverse (5300000015501), we get a palindrome (6355100015536).
The spelling of 1055100000035 in words is "one trillion, fifty-five billion, one hundred million, thirty-five", and thus it is an aban number.
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