Base | Representation |
---|---|
bin | 1001111111111111110011… |
… | …0101010100110100101111 |
3 | 1102221010011212002121021111 |
4 | 2133333330311110310233 |
5 | 2420120342131212243 |
6 | 35215021241412451 |
7 | 2213236625503306 |
oct | 237777465246457 |
9 | 42833155077244 |
10 | 10995063147823 |
11 | 3559a86562897 |
12 | 1296b0049a127 |
13 | 619aa36a5151 |
14 | 2a0241a3143d |
15 | 14101807839d |
hex | 9fffcd54d2f |
10995063147823 has 2 divisors, whose sum is σ = 10995063147824. Its totient is φ = 10995063147822.
The previous prime is 10995063147799. The next prime is 10995063147847. The reversal of 10995063147823 is 32874136059901.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (10995063147799) and next prime (10995063147847).
It is a cyclic number.
It is not a de Polignac number, because 10995063147823 - 233 = 10986473213231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (10995066147823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5497531573911 + 5497531573912.
It is an arithmetic number, because the mean of its divisors is an integer number (5497531573912).
It is a 1-persistent number, because it is pandigital, but 2⋅10995063147823 = 21990126295646 is not.
Almost surely, 210995063147823 is an apocalyptic number.
10995063147823 is a deficient number, since it is larger than the sum of its proper divisors (1).
10995063147823 is an equidigital number, since it uses as much as digits as its factorization.
10995063147823 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9797760, while the sum is 58.
The spelling of 10995063147823 in words is "ten trillion, nine hundred ninety-five billion, sixty-three million, one hundred forty-seven thousand, eight hundred twenty-three".
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