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10995063147823 is a prime number
BaseRepresentation
bin1001111111111111110011…
…0101010100110100101111
31102221010011212002121021111
42133333330311110310233
52420120342131212243
635215021241412451
72213236625503306
oct237777465246457
942833155077244
1010995063147823
113559a86562897
121296b0049a127
13619aa36a5151
142a0241a3143d
1514101807839d
hex9fffcd54d2f

10995063147823 has 2 divisors, whose sum is σ = 10995063147824. Its totient is φ = 10995063147822.

The previous prime is 10995063147799. The next prime is 10995063147847. The reversal of 10995063147823 is 32874136059901.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (10995063147799) and next prime (10995063147847).

It is a cyclic number.

It is not a de Polignac number, because 10995063147823 - 233 = 10986473213231 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (10995066147823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5497531573911 + 5497531573912.

It is an arithmetic number, because the mean of its divisors is an integer number (5497531573912).

It is a 1-persistent number, because it is pandigital, but 2⋅10995063147823 = 21990126295646 is not.

Almost surely, 210995063147823 is an apocalyptic number.

10995063147823 is a deficient number, since it is larger than the sum of its proper divisors (1).

10995063147823 is an equidigital number, since it uses as much as digits as its factorization.

10995063147823 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9797760, while the sum is 58.

The spelling of 10995063147823 in words is "ten trillion, nine hundred ninety-five billion, sixty-three million, one hundred forty-seven thousand, eight hundred twenty-three".