110000000001401 has 2 divisors, whose sum is σ = 110000000001402. Its totient is φ = 110000000001400.

The previous prime is 110000000001391. The next prime is 110000000001427. The reversal of 110000000001401 is 104100000000011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106076589823801 + 3923410177600 = 10299349^2 + 1980760^2 .

It is an emirp because it is prime and its reverse (104100000000011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110000000001401 is a prime.

It is not a weakly prime, because it can be changed into another prime (110000000001461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000000000700 + 55000000000701.

It is an arithmetic number, because the mean of its divisors is an integer number (55000000000701).

Almost surely, 2^{110000000001401} is an apocalyptic number.

It is an amenable number.

110000000001401 is a deficient number, since it is larger than the sum of its proper divisors (1).

110000000001401 is an equidigital number, since it uses as much as digits as its factorization.

110000000001401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 8.

Adding to 110000000001401 its reverse (104100000000011), we get a palindrome (214100000001412).

The spelling of 110000000001401 in words is "one hundred ten trillion, one thousand, four hundred one".