Base | Representation |
---|---|
bin | 10111101010110110101011… |
… | …100001010110100000001011 |
3 | 111122120212021222122120110222 |
4 | 113222312223201112200023 |
5 | 102121033300000000021 |
6 | 1005222514011500255 |
7 | 30632656021134041 |
oct | 2752665341264013 |
9 | 448525258576428 |
10 | 104100000000011 |
11 | 30195620133954 |
12 | b81333b45768b |
13 | 4611784751102 |
14 | 1b9c6771b2391 |
15 | c07d2e9b46ab |
hex | 5eadab85680b |
104100000000011 has 2 divisors, whose sum is σ = 104100000000012. Its totient is φ = 104100000000010.
The previous prime is 104099999999953. The next prime is 104100000000013. The reversal of 104100000000011 is 110000000001401.
It is a strong prime.
It is an emirp because it is prime and its reverse (110000000001401) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 104100000000011 - 210 = 104099999998987 is a prime.
It is a Sophie Germain prime.
Together with 104100000000013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (104100000000013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 52050000000005 + 52050000000006.
It is an arithmetic number, because the mean of its divisors is an integer number (52050000000006).
Almost surely, 2104100000000011 is an apocalyptic number.
104100000000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
104100000000011 is an equidigital number, since it uses as much as digits as its factorization.
104100000000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4, while the sum is 8.
Adding to 104100000000011 its reverse (110000000001401), we get a palindrome (214100000001412).
The spelling of 104100000000011 in words is "one hundred four trillion, one hundred billion, eleven", and thus it is an aban number.
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