Base | Representation |
---|---|
bin | 1010000000010010001100… |
… | …1001101111011010001111 |
3 | 1102221120220222112112120022 |
4 | 2200010203021233122033 |
5 | 2420211000224013403 |
6 | 35221155233012355 |
7 | 2213503164533102 |
oct | 240044311573217 |
9 | 42846828475508 |
10 | 11000001001103 |
11 | 356108a883074 |
12 | 1297a5a0b40bb |
13 | 61a3ac6b491a |
14 | 2a058d756739 |
15 | 141206805d38 |
hex | a012326f68f |
11000001001103 has 2 divisors, whose sum is σ = 11000001001104. Its totient is φ = 11000001001102.
The previous prime is 11000001001091. The next prime is 11000001001111. The reversal of 11000001001103 is 30110010000011.
It is an a-pointer prime, because the next prime (11000001001111) can be obtained adding 11000001001103 to its sum of digits (8).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11000001001103 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11000001061103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500000500551 + 5500000500552.
It is an arithmetic number, because the mean of its divisors is an integer number (5500000500552).
Almost surely, 211000001001103 is an apocalyptic number.
11000001001103 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000001001103 is an equidigital number, since it uses as much as digits as its factorization.
11000001001103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3, while the sum is 8.
Adding to 11000001001103 its reverse (30110010000011), we get a palindrome (41110011001114).
The spelling of 11000001001103 in words is "eleven trillion, one million, one thousand, one hundred three".
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