Base | Representation |
---|---|
bin | 11001000000101101011111… |
… | …101001110000100010100111 |
3 | 112102110220020222111121111202 |
4 | 121000231133221300202213 |
5 | 103404220011110400403 |
6 | 1025541150305153115 |
7 | 32112144563311424 |
oct | 3100553751604247 |
9 | 472426228447452 |
10 | 110000012200103 |
11 | 3205a81a213323 |
12 | 104068a562b79b |
13 | 494bc5898355c |
14 | 1d240597d8d4b |
15 | cab545822688 |
hex | 640b5fa708a7 |
110000012200103 has 2 divisors, whose sum is σ = 110000012200104. Its totient is φ = 110000012200102.
The previous prime is 110000012200063. The next prime is 110000012200157. The reversal of 110000012200103 is 301002210000011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110000012200103 - 216 = 110000012134567 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110000012230103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000006100051 + 55000006100052.
It is an arithmetic number, because the mean of its divisors is an integer number (55000006100052).
Almost surely, 2110000012200103 is an apocalyptic number.
110000012200103 is a deficient number, since it is larger than the sum of its proper divisors (1).
110000012200103 is an equidigital number, since it uses as much as digits as its factorization.
110000012200103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 110000012200103 its reverse (301002210000011), we get a palindrome (411002222200114).
The spelling of 110000012200103 in words is "one hundred ten trillion, twelve million, two hundred thousand, one hundred three".
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