1100001100127 has 2 divisors, whose sum is σ = 1100001100128. Its totient is φ = 1100001100126.

The previous prime is 1100001100123. The next prime is 1100001100129. The reversal of 1100001100127 is 7210011000011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100001100127 - 2² = 1100001100123 is a prime.

It is a super-2 number, since 2×1100001100127² (a number of 25 digits) contains 22 as substring.

Together with 1100001100129, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100001100123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550000550063 + 550000550064.

It is an arithmetic number, because the mean of its divisors is an integer number (550000550064).

Almost surely, 2^{1100001100127} is an apocalyptic number.

1100001100127 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100001100127 is an equidigital number, since it uses as much as digits as its factorization.

1100001100127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14, while the sum is 14.

Adding to 1100001100127 its reverse (7210011000011), we get a palindrome (8310012100138).

The spelling of 1100001100127 in words is "one trillion, one hundred billion, one million, one hundred thousand, one hundred twenty-seven".