Base | Representation |
---|---|
bin | 10100011111010011… |
… | …10010100001000100 |
3 | 1001101121111111011200 |
4 | 22033221302201010 |
5 | 140012002000200 |
6 | 5015304502500 |
7 | 536406503046 |
oct | 121751624104 |
9 | 31347444150 |
10 | 11000031300 |
11 | 473525a365 |
12 | 216ba7aa30 |
13 | 1063c3897b |
14 | 764cbba96 |
15 | 445a98800 |
hex | 28fa72844 |
11000031300 has 54 divisors (see below), whose sum is σ = 34478989818. Its totient is φ = 2933341440.
The previous prime is 11000031299. The next prime is 11000031307. The reversal of 11000031300 is 313000011.
It can be written as a sum of positive squares in 3 ways, for example, as 920272896 + 10079758404 = 30336^2 + 100398^2 .
It is a Harshad number since it is a multiple of its sum of digits (9).
It is not an unprimeable number, because it can be changed into a prime (11000031307) by changing a digit.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 6110229 + ... + 6112028.
Almost surely, 211000031300 is an apocalyptic number.
11000031300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
11000031300 is an abundant number, since it is smaller than the sum of its proper divisors (23478958518).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11000031300 is a wasteful number, since it uses less digits than its factorization.
11000031300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12222277 (or 12222267 counting only the distinct ones).
The product of its (nonzero) digits is 9, while the sum is 9.
Adding to 11000031300 its reverse (313000011), we get a palindrome (11313031311).
The spelling of 11000031300 in words is "eleven billion, thirty-one thousand, three hundred".
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