11000100999947 has 2 divisors, whose sum is σ = 11000100999948. Its totient is φ = 11000100999946.

The previous prime is 11000100999931. The next prime is 11000100999949. The reversal of 11000100999947 is 74999900100011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11000100999947 - 2⁴ = 11000100999931 is a prime.

Together with 11000100999949, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000100999895 and 11000100999904.

It is not a weakly prime, because it can be changed into another prime (11000100999949) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500050499973 + 5500050499974.

It is an arithmetic number, because the mean of its divisors is an integer number (5500050499974).

Almost surely, 2^{11000100999947} is an apocalyptic number.

11000100999947 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000100999947 is an equidigital number, since it uses as much as digits as its factorization.

11000100999947 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 183708, while the sum is 50.

The spelling of 11000100999947 in words is "eleven trillion, one hundred million, nine hundred ninety-nine thousand, nine hundred forty-seven".