Base | Representation |
---|---|
bin | 1010000000010010100111… |
… | …0001001111101010000110 |
3 | 1102221121012201102220000002 |
4 | 2200010221301033222012 |
5 | 2420211212134120402 |
6 | 35221214240321302 |
7 | 2213506013300462 |
oct | 240045161175206 |
9 | 42847181386002 |
10 | 11000112020102 |
11 | 3561137510307 |
12 | 1297a8b313232 |
13 | 61a3c96b5a3a |
14 | 2a05a03b54a2 |
15 | 141211435602 |
hex | a0129c4fa86 |
11000112020102 has 4 divisors (see below), whose sum is σ = 16500168030156. Its totient is φ = 5500056010050.
The previous prime is 11000112020089. The next prime is 11000112020111. The reversal of 11000112020102 is 20102021100011.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×110001120201023 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750028005024 + ... + 2750028005027.
It is an arithmetic number, because the mean of its divisors is an integer number (4125042007539).
Almost surely, 211000112020102 is an apocalyptic number.
11000112020102 is a deficient number, since it is larger than the sum of its proper divisors (5500056010054).
11000112020102 is an equidigital number, since it uses as much as digits as its factorization.
11000112020102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5500056010053.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 11000112020102 its reverse (20102021100011), we get a palindrome (31102133120113).
The spelling of 11000112020102 in words is "eleven trillion, one hundred twelve million, twenty thousand, one hundred two".
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