Base | Representation |
---|---|
bin | 11001000000101110100111… |
… | …101101011011000011001111 |
3 | 112102111000101020022010010102 |
4 | 121000232213231123003033 |
5 | 103404230000101321312 |
6 | 1025541510252401315 |
7 | 32112216543051014 |
oct | 3100564755330317 |
9 | 472430336263112 |
10 | 110001221120207 |
11 | 3206028a66194a |
12 | 10406b8247623b |
13 | 494c0bc27bbb1 |
14 | 1d241321ab70b |
15 | cab5b6a20ec2 |
hex | 640ba7b5b0cf |
110001221120207 has 2 divisors, whose sum is σ = 110001221120208. Its totient is φ = 110001221120206.
The previous prime is 110001221120123. The next prime is 110001221120209. The reversal of 110001221120207 is 702021122100011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110001221120207 - 228 = 110000952684751 is a prime.
Together with 110001221120209, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110001221120209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000610560103 + 55000610560104.
It is an arithmetic number, because the mean of its divisors is an integer number (55000610560104).
Almost surely, 2110001221120207 is an apocalyptic number.
110001221120207 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001221120207 is an equidigital number, since it uses as much as digits as its factorization.
110001221120207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 20.
Adding to 110001221120207 its reverse (702021122100011), we get a palindrome (812022343220218).
The spelling of 110001221120207 in words is "one hundred ten trillion, one billion, two hundred twenty-one million, one hundred twenty thousand, two hundred seven".
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