1100013300013 has 2 divisors, whose sum is σ = 1100013300014. Its totient is φ = 1100013300012.

The previous prime is 1100013299989. The next prime is 1100013300077. The reversal of 1100013300013 is 3100033100011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 876848705604 + 223164594409 = 936402^2 + 472403^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100013300013 - 2⁵ = 1100013299981 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100013299966 and 1100013300002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100013309013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006650006 + 550006650007.

It is an arithmetic number, because the mean of its divisors is an integer number (550006650007).

Almost surely, 2^{1100013300013} is an apocalyptic number.

It is an amenable number.

1100013300013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013300013 is an equidigital number, since it uses as much as digits as its factorization.

1100013300013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 1100013300013 its reverse (3100033100011), we get a palindrome (4200046400024).

The spelling of 1100013300013 in words is "one trillion, one hundred billion, thirteen million, three hundred thousand, thirteen".