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11000141300 = 2252110001413
BaseRepresentation
bin10100011111010100…
…01101010111110100
31001101121201002001202
422033222031113310
5140012014010200
65015311112032
7536410441541
oct121752152764
931347632052
1011000141300
114735324a75
12216bb12618
131063c76a65
14764d09bc8
15445abb1d5
hex28fa8d5f4

11000141300 has 18 divisors (see below), whose sum is σ = 23870306838. Its totient is φ = 4400056480.

The previous prime is 11000141263. The next prime is 11000141303. The reversal of 11000141300 is 314100011.

It can be written as a sum of positive squares in 3 ways, for example, as 175403536 + 10824737764 = 13244^2 + 104042^2 .

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000141303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 55000607 + ... + 55000806.

Almost surely, 211000141300 is an apocalyptic number.

11000141300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11000141300 is an abundant number, since it is smaller than the sum of its proper divisors (12870165538).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000141300 is a wasteful number, since it uses less digits than its factorization.

11000141300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110001427 (or 110001420 counting only the distinct ones).

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 11000141300 its reverse (314100011), we get a palindrome (11314241311).

The spelling of 11000141300 in words is "eleven billion, one hundred forty-one thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 110001413 220002826 440005652 550007065 1100014130 2200028260 2750035325 5500070650 11000141300