Base | Representation |
---|---|
bin | 1010000000010010111100… |
… | …1000100100100110001001 |
3 | 1102221121102222210102101012 |
4 | 2200010233020210212021 |
5 | 2420211403204140012 |
6 | 35221231213333305 |
7 | 2213511155266511 |
oct | 240045710444611 |
9 | 42847388712335 |
10 | 11000202021257 |
11 | 35611832a2529 |
12 | 1297ab5497235 |
13 | 61a412238367 |
14 | 2a05ac322841 |
15 | 1412192b2622 |
hex | a012f224989 |
11000202021257 has 2 divisors, whose sum is σ = 11000202021258. Its totient is φ = 11000202021256.
The previous prime is 11000202021197. The next prime is 11000202021317. The reversal of 11000202021257 is 75212020200011.
It is a balanced prime because it is at equal distance from previous prime (11000202021197) and next prime (11000202021317).
It can be written as a sum of positive squares in only one way, i.e., 9289505441161 + 1710696580096 = 3047869^2 + 1307936^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000202021257 - 210 = 11000202020233 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000202021857) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500101010628 + 5500101010629.
It is an arithmetic number, because the mean of its divisors is an integer number (5500101010629).
Almost surely, 211000202021257 is an apocalyptic number.
It is an amenable number.
11000202021257 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000202021257 is an equidigital number, since it uses as much as digits as its factorization.
11000202021257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 560, while the sum is 23.
Adding to 11000202021257 its reverse (75212020200011), we get a palindrome (86212222221268).
The spelling of 11000202021257 in words is "eleven trillion, two hundred two million, twenty-one thousand, two hundred fifty-seven".
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