11000204311 has 2 divisors, whose sum is σ = 11000204312. Its totient is φ = 11000204310.

The previous prime is 11000204309. The next prime is 11000204321. The reversal of 11000204311 is 11340200011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11000204311 - 2¹ = 11000204309 is a prime.

Together with 11000204309, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 11000204291 and 11000204300.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11000204321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500102155 + 5500102156.

It is an arithmetic number, because the mean of its divisors is an integer number (5500102156).

Almost surely, 2^11000204311 is an apocalyptic number.

11000204311 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000204311 is an equidigital number, since it uses as much as digits as its factorization.

11000204311 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 11000204311 its reverse (11340200011), we get a palindrome (22340404322).

The spelling of 11000204311 in words is "eleven billion, two hundred four thousand, three hundred eleven".