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110002054453 is a prime number
BaseRepresentation
bin110011001110010100…
…0100010010100110101
3101111221020021100112221
41212130220202110311
53300241011220303
6122311221442341
710642645015054
oct1463450422465
9344836240487
10110002054453
1142719323705
121939b5703b1
13a4b0a69065
14547759a39b
152cdc3a14bd
hex199ca22535

110002054453 has 2 divisors, whose sum is σ = 110002054454. Its totient is φ = 110002054452.

The previous prime is 110002054441. The next prime is 110002054541. The reversal of 110002054453 is 354450200011.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 79032390129 + 30969664324 = 281127^2 + 175982^2 .

It is an emirp because it is prime and its reverse (354450200011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110002054453 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110002054153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001027226 + 55001027227.

It is an arithmetic number, because the mean of its divisors is an integer number (55001027227).

Almost surely, 2110002054453 is an apocalyptic number.

It is an amenable number.

110002054453 is a deficient number, since it is larger than the sum of its proper divisors (1).

110002054453 is an equidigital number, since it uses as much as digits as its factorization.

110002054453 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 25.

Adding to 110002054453 its reverse (354450200011), we get a palindrome (464452254464).

The spelling of 110002054453 in words is "one hundred ten billion, two million, fifty-four thousand, four hundred fifty-three".