Base | Representation |
---|---|
bin | 10100011111010100… |
… | …11111001100111111 |
3 | 1001101121211210020202 |
4 | 22033222133030333 |
5 | 140012023324320 |
6 | 5015312434115 |
7 | 536411164505 |
oct | 121752371477 |
9 | 31347753222 |
10 | 11000214335 |
11 | 4735374930 |
12 | 216bb4893b |
13 | 1063ca1086 |
14 | 764d28675 |
15 | 445ad2b75 |
hex | 28fa9f33f |
11000214335 has 8 divisors (see below), whose sum is σ = 14400280656. Its totient is φ = 8000155840.
The previous prime is 11000214317. The next prime is 11000214359. The reversal of 11000214335 is 53341200011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 11000214335 - 210 = 11000213311 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 100001894 + ... + 100002003.
It is an arithmetic number, because the mean of its divisors is an integer number (1800035082).
Almost surely, 211000214335 is an apocalyptic number.
11000214335 is a deficient number, since it is larger than the sum of its proper divisors (3400066321).
11000214335 is a wasteful number, since it uses less digits than its factorization.
11000214335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 200003913.
The product of its (nonzero) digits is 360, while the sum is 20.
Adding to 11000214335 its reverse (53341200011), we get a palindrome (64341414346).
The spelling of 11000214335 in words is "eleven billion, two hundred fourteen thousand, three hundred thirty-five".
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