Base | Representation |
---|---|
bin | 1010000000010011000011… |
… | …1101000010000000000011 |
3 | 1102221121112010020110111022 |
4 | 2200010300331002000003 |
5 | 2420211434013103103 |
6 | 35221234223540055 |
7 | 2213512005630665 |
oct | 240046075020003 |
9 | 42847463213438 |
10 | 11000232550403 |
11 | 3561199554528 |
12 | 1297b0375a62b |
13 | 61a418667145 |
14 | 2a05b23cc535 |
15 | 14121bce3138 |
hex | a0130f42003 |
11000232550403 has 4 divisors (see below), whose sum is σ = 11379550914240. Its totient is φ = 10620914186568.
The previous prime is 11000232550399. The next prime is 11000232550427. The reversal of 11000232550403 is 30405523200011.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11000232550403 - 22 = 11000232550399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11000232550493) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 189659181875 + ... + 189659181932.
It is an arithmetic number, because the mean of its divisors is an integer number (2844887728560).
Almost surely, 211000232550403 is an apocalyptic number.
11000232550403 is a deficient number, since it is larger than the sum of its proper divisors (379318363837).
11000232550403 is an equidigital number, since it uses as much as digits as its factorization.
11000232550403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 379318363836.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 11000232550403 its reverse (30405523200011), we get a palindrome (41405755750414).
The spelling of 11000232550403 in words is "eleven trillion, two hundred thirty-two million, five hundred fifty thousand, four hundred three".
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