110010011140111 has 2 divisors, whose sum is σ = 110010011140112. Its totient is φ = 110010011140110.

The previous prime is 110010011140067. The next prime is 110010011140121. The reversal of 110010011140111 is 111041110010011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110010011140111 - 2⁷ = 110010011139983 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110010011140091 and 110010011140100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110010011140121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005005570055 + 55005005570056.

It is an arithmetic number, because the mean of its divisors is an integer number (55005005570056).

Almost surely, 2^{110010011140111} is an apocalyptic number.

110010011140111 is a deficient number, since it is larger than the sum of its proper divisors (1).

110010011140111 is an equidigital number, since it uses as much as digits as its factorization.

110010011140111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 110010011140111 its reverse (111041110010011), we get a palindrome (221051121150122).

The spelling of 110010011140111 in words is "one hundred ten trillion, ten billion, eleven million, one hundred forty thousand, one hundred eleven".