Base | Representation |
---|---|
bin | 1010000000010101111101… |
… | …0110100111100111100111 |
3 | 1102221200112101001022100002 |
4 | 2200011133112213213213 |
5 | 2420220032304310043 |
6 | 35221443353011515 |
7 | 2213540210501366 |
oct | 240053726474747 |
9 | 42850471038302 |
10 | 11001011010023 |
11 | 3561558a12791 |
12 | 12980a03b3b9b |
13 | 61a510a17738 |
14 | 2a064794b7dd |
15 | 141265312bb8 |
hex | a015f5a79e7 |
11001011010023 has 2 divisors, whose sum is σ = 11001011010024. Its totient is φ = 11001011010022.
The previous prime is 11001011009971. The next prime is 11001011010061. The reversal of 11001011010023 is 32001011010011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001011010023 - 28 = 11001011009767 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11001011009986 and 11001011010013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001011010083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500505505011 + 5500505505012.
It is an arithmetic number, because the mean of its divisors is an integer number (5500505505012).
Almost surely, 211001011010023 is an apocalyptic number.
11001011010023 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001011010023 is an equidigital number, since it uses as much as digits as its factorization.
11001011010023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 11001011010023 its reverse (32001011010011), we get a palindrome (43002022020034).
The spelling of 11001011010023 in words is "eleven trillion, one billion, eleven million, ten thousand, twenty-three".
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