Base | Representation |
---|---|
bin | 10100011111011011… |
… | …00001111110100101 |
3 | 1001101200100022121211 |
4 | 22033231201332211 |
5 | 140012224342013 |
6 | 5015341511421 |
7 | 536421026446 |
oct | 121755417645 |
9 | 31350308554 |
10 | 11001012133 |
11 | 473586a271 |
12 | 2170272571 |
13 | 10641c0247 |
14 | 7650952cd |
15 | 445bde23d |
hex | 28fb61fa5 |
11001012133 has 2 divisors, whose sum is σ = 11001012134. Its totient is φ = 11001012132.
The previous prime is 11001012131. The next prime is 11001012157. The reversal of 11001012133 is 33121010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10264323969 + 736688164 = 101313^2 + 27142^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001012133 - 21 = 11001012131 is a prime.
Together with 11001012131, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001012131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500506066 + 5500506067.
It is an arithmetic number, because the mean of its divisors is an integer number (5500506067).
Almost surely, 211001012133 is an apocalyptic number.
It is an amenable number.
11001012133 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001012133 is an equidigital number, since it uses as much as digits as its factorization.
11001012133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11001012133 its reverse (33121010011), we get a palindrome (44122022144).
The spelling of 11001012133 in words is "eleven billion, one million, twelve thousand, one hundred thirty-three".
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