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11001021210022 = 25500510605011
BaseRepresentation
bin1010000000010101111111…
…1101100001110110100110
31102221200120002020112002211
42200011133331201312212
52420220042412210042
635221444355354034
72213540363263114
oct240053775416646
942850502215084
1011001021210022
11356156374a138
1212980a38b291a
1361a512b7933c
142a0649044ab4
1514126617a017
hexa015ff61da6

11001021210022 has 4 divisors (see below), whose sum is σ = 16501531815036. Its totient is φ = 5500510605010.

The previous prime is 11001021210013. The next prime is 11001021210041. The reversal of 11001021210022 is 22001212010011.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 11001021209984 and 11001021210011.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750255302504 + ... + 2750255302507.

It is an arithmetic number, because the mean of its divisors is an integer number (4125382953759).

Almost surely, 211001021210022 is an apocalyptic number.

11001021210022 is a deficient number, since it is larger than the sum of its proper divisors (5500510605014).

11001021210022 is an equidigital number, since it uses as much as digits as its factorization.

11001021210022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5500510605013.

The product of its (nonzero) digits is 16, while the sum is 13.

Adding to 11001021210022 its reverse (22001212010011), we get a palindrome (33002233220033).

The spelling of 11001021210022 in words is "eleven trillion, one billion, twenty-one million, two hundred ten thousand, twenty-two".

Divisors: 1 2 5500510605011 11001021210022