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1100110000063 is a prime number
BaseRepresentation
bin10000000000100011101…
…010100110111110111111
310220011120120001100110011
4100000203222212332333
5121011011130000223
62201214503124051
7142323515466304
oct20004352467677
93804516040404
101100110000063
11394610462738
12159260743627
137c980810679
143b361d3d0ab
151d93a47d80d
hex10023aa6fbf

1100110000063 has 2 divisors, whose sum is σ = 1100110000064. Its totient is φ = 1100110000062.

The previous prime is 1100110000051. The next prime is 1100110000111. The reversal of 1100110000063 is 3600000110011.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100110000063 - 29 = 1100109999551 is a prime.

It is a super-2 number, since 2×11001100000632 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100109999998 and 1100110000052.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100110000043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055000031 + 550055000032.

It is an arithmetic number, because the mean of its divisors is an integer number (550055000032).

Almost surely, 21100110000063 is an apocalyptic number.

1100110000063 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100110000063 is an equidigital number, since it uses as much as digits as its factorization.

1100110000063 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1100110000063 its reverse (3600000110011), we get a palindrome (4700110110074).

The spelling of 1100110000063 in words is "one trillion, one hundred billion, one hundred ten million, sixty-three", and thus it is an aban number.