Base | Representation |
---|---|
bin | 10000000000100011101… |
… | …010100110111110111111 |
3 | 10220011120120001100110011 |
4 | 100000203222212332333 |
5 | 121011011130000223 |
6 | 2201214503124051 |
7 | 142323515466304 |
oct | 20004352467677 |
9 | 3804516040404 |
10 | 1100110000063 |
11 | 394610462738 |
12 | 159260743627 |
13 | 7c980810679 |
14 | 3b361d3d0ab |
15 | 1d93a47d80d |
hex | 10023aa6fbf |
1100110000063 has 2 divisors, whose sum is σ = 1100110000064. Its totient is φ = 1100110000062.
The previous prime is 1100110000051. The next prime is 1100110000111. The reversal of 1100110000063 is 3600000110011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100110000063 - 29 = 1100109999551 is a prime.
It is a super-2 number, since 2×11001100000632 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1100109999998 and 1100110000052.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100110000043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055000031 + 550055000032.
It is an arithmetic number, because the mean of its divisors is an integer number (550055000032).
Almost surely, 21100110000063 is an apocalyptic number.
1100110000063 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100110000063 is an equidigital number, since it uses as much as digits as its factorization.
1100110000063 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 1100110000063 its reverse (3600000110011), we get a palindrome (4700110110074).
The spelling of 1100110000063 in words is "one trillion, one hundred billion, one hundred ten million, sixty-three", and thus it is an aban number.
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