110011010000053 has 2 divisors, whose sum is σ = 110011010000054. Its totient is φ = 110011010000052.

The previous prime is 110011010000027. The next prime is 110011010000123. The reversal of 110011010000053 is 350000010110011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106842674079729 + 3168335920324 = 10336473^2 + 1779982^2 .

It is a cyclic number.

It is not a de Polignac number, because 110011010000053 - 2²⁵ = 110010976445621 is a prime.

It is a super-2 number, since 2×110011010000053² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110011009999988 and 110011010000042.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011010004053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005505000026 + 55005505000027.

It is an arithmetic number, because the mean of its divisors is an integer number (55005505000027).

Almost surely, 2^{110011010000053} is an apocalyptic number.

It is an amenable number.

110011010000053 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011010000053 is an equidigital number, since it uses as much as digits as its factorization.

110011010000053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15, while the sum is 13.

Adding to 110011010000053 its reverse (350000010110011), we get a palindrome (460011020110064).

The spelling of 110011010000053 in words is "one hundred ten trillion, eleven billion, ten million, fifty-three", and thus it is an aban number.