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110011109983 is a prime number
BaseRepresentation
bin110011001110100101…
…1000101001001011111
3101111221212022102101221
41212131023011021133
53300300321004413
6122312143514211
710643115002035
oct1463513051137
9344855272357
10110011109983
1142723449215
12193a25b8967
13a4b28b9a68
145478876555
152cdd08e68d
hex199d2c525f

110011109983 has 2 divisors, whose sum is σ = 110011109984. Its totient is φ = 110011109982.

The previous prime is 110011109981. The next prime is 110011110023. The reversal of 110011109983 is 389901110011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110011109983 - 21 = 110011109981 is a prime.

Together with 110011109981, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011109981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005554991 + 55005554992.

It is an arithmetic number, because the mean of its divisors is an integer number (55005554992).

Almost surely, 2110011109983 is an apocalyptic number.

110011109983 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011109983 is an equidigital number, since it uses as much as digits as its factorization.

110011109983 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 34.

Adding to 110011109983 its reverse (389901110011), we get a palindrome (499912219994).

The spelling of 110011109983 in words is "one hundred ten billion, eleven million, one hundred nine thousand, nine hundred eighty-three".