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110011110023 is a prime number
BaseRepresentation
bin110011001110100101…
…1000101001010000111
3101111221212022102110102
41212131023011022013
53300300321010043
6122312143514315
710643115002123
oct1463513051207
9344855272412
10110011110023
1142723449251
12193a25b899b
13a4b28b9a99
145478876583
152cdd08e6b8
hex199d2c5287

110011110023 has 2 divisors, whose sum is σ = 110011110024. Its totient is φ = 110011110022.

The previous prime is 110011109983. The next prime is 110011110059. The reversal of 110011110023 is 320011110011.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (320011110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110011110023 - 212 = 110011105927 is a prime.

It is a super-2 number, since 2×1100111100232 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110011109986 and 110011110013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011110623) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005555011 + 55005555012.

It is an arithmetic number, because the mean of its divisors is an integer number (55005555012).

Almost surely, 2110011110023 is an apocalyptic number.

110011110023 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011110023 is an equidigital number, since it uses as much as digits as its factorization.

110011110023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 110011110023 its reverse (320011110011), we get a palindrome (430022220034).

The spelling of 110011110023 in words is "one hundred ten billion, eleven million, one hundred ten thousand, twenty-three".