Base | Representation |
---|---|
bin | 110011001110100101… |
… | …1000101001010000111 |
3 | 101111221212022102110102 |
4 | 1212131023011022013 |
5 | 3300300321010043 |
6 | 122312143514315 |
7 | 10643115002123 |
oct | 1463513051207 |
9 | 344855272412 |
10 | 110011110023 |
11 | 42723449251 |
12 | 193a25b899b |
13 | a4b28b9a99 |
14 | 5478876583 |
15 | 2cdd08e6b8 |
hex | 199d2c5287 |
110011110023 has 2 divisors, whose sum is σ = 110011110024. Its totient is φ = 110011110022.
The previous prime is 110011109983. The next prime is 110011110059. The reversal of 110011110023 is 320011110011.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (320011110011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110011110023 - 212 = 110011105927 is a prime.
It is a super-2 number, since 2×1100111100232 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110011109986 and 110011110013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110011110623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005555011 + 55005555012.
It is an arithmetic number, because the mean of its divisors is an integer number (55005555012).
Almost surely, 2110011110023 is an apocalyptic number.
110011110023 is a deficient number, since it is larger than the sum of its proper divisors (1).
110011110023 is an equidigital number, since it uses as much as digits as its factorization.
110011110023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 110011110023 its reverse (320011110011), we get a palindrome (430022220034).
The spelling of 110011110023 in words is "one hundred ten billion, eleven million, one hundred ten thousand, twenty-three".
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