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110011210100023 is a prime number
BaseRepresentation
bin11001000000110111111011…
…000110010110110100110111
3112102111222011101022212101211
4121000313323012112310313
5103404410424241200043
61025550241403102251
732113022225014111
oct3100677306266467
9472458141285354
10110011210100023
113206454612a271
1210408aab811987
1349500218ab33b
141d247dcaa23b1
15cab99d953a9d
hex640dfb196d37

110011210100023 has 2 divisors, whose sum is σ = 110011210100024. Its totient is φ = 110011210100022.

The previous prime is 110011210099991. The next prime is 110011210100171. The reversal of 110011210100023 is 320001012110011.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (320001012110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110011210100023 - 25 = 110011210099991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110011210099976 and 110011210100012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011210107023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005605050011 + 55005605050012.

It is an arithmetic number, because the mean of its divisors is an integer number (55005605050012).

Almost surely, 2110011210100023 is an apocalyptic number.

110011210100023 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011210100023 is an equidigital number, since it uses as much as digits as its factorization.

110011210100023 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 13.

Adding to 110011210100023 its reverse (320001012110011), we get a palindrome (430012222210034).

The spelling of 110011210100023 in words is "one hundred ten trillion, eleven billion, two hundred ten million, one hundred thousand, twenty-three".