1100113241232 has 20 divisors (see below), whose sum is σ = 2841959206640. Its totient is φ = 366704413728.

The previous prime is 1100113241197. The next prime is 1100113241299. The reversal of 1100113241232 is 2321423110011.

It is a super-3 number, since 3×1100113241232³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100113241199 and 1100113241208.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11459512882 + ... + 11459512977.

It is an arithmetic number, because the mean of its divisors is an integer number (142097960332).

Almost surely, 2^{1100113241232} is an apocalyptic number.

1100113241232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1100113241232 is an abundant number, since it is smaller than the sum of its proper divisors (1741845965408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1100113241232 is a wasteful number, since it uses less digits than its factorization.

1100113241232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22919025870 (or 22919025864 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1100113241232 its reverse (2321423110011), we get a palindrome (3421536351243).

The spelling of 1100113241232 in words is "one trillion, one hundred billion, one hundred thirteen million, two hundred forty-one thousand, two hundred thirty-two".