Base | Representation |
---|---|
bin | 1010000000010110101111… |
… | …1100010010000111111111 |
3 | 1102221201002002110101022012 |
4 | 2200011223330102013333 |
5 | 2420221000341210142 |
6 | 35221520335441435 |
7 | 2213545353614036 |
oct | 240055374220777 |
9 | 42851062411265 |
10 | 11001222210047 |
11 | 3561657155463 |
12 | 129813b08627b |
13 | 61a5456c3874 |
14 | 2a0667a0771d |
15 | 141278b30882 |
hex | a016bf121ff |
11001222210047 has 2 divisors, whose sum is σ = 11001222210048. Its totient is φ = 11001222210046.
The previous prime is 11001222209917. The next prime is 11001222210137. The reversal of 11001222210047 is 74001222210011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11001222210047 is a prime.
It is a super-2 number, since 2×110012222100472 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001222210247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500611105023 + 5500611105024.
It is an arithmetic number, because the mean of its divisors is an integer number (5500611105024).
Almost surely, 211001222210047 is an apocalyptic number.
11001222210047 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001222210047 is an equidigital number, since it uses as much as digits as its factorization.
11001222210047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 11001222210047 its reverse (74001222210011), we get a palindrome (85002444420058).
The spelling of 11001222210047 in words is "eleven trillion, one billion, two hundred twenty-two million, two hundred ten thousand, forty-seven".
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