11001232201301 has 4 divisors (see below), whose sum is σ = 11081533166412. Its totient is φ = 10920931236192.

The previous prime is 11001232201291. The next prime is 11001232201331. The reversal of 11001232201301 is 10310223210011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7534750502500 + 3466481698801 = 2744950^2 + 1861849^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001232201301 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11001232201301.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001232201331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40150482350 + ... + 40150482623.

It is an arithmetic number, because the mean of its divisors is an integer number (2770383291603).

Almost surely, 2^{11001232201301} is an apocalyptic number.

It is an amenable number.

11001232201301 is a deficient number, since it is larger than the sum of its proper divisors (80300965111).

11001232201301 is an equidigital number, since it uses as much as digits as its factorization.

11001232201301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 80300965110.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 11001232201301 its reverse (10310223210011), we get a palindrome (21311455411312).

The spelling of 11001232201301 in words is "eleven trillion, one billion, two hundred thirty-two million, two hundred one thousand, three hundred one".