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110020000122022 = 2471170425533213
BaseRepresentation
bin11001000001000000000111…
…000001101000010010100110
3112102112210211222022020202011
4121001000013001220102212
5103410031430012401042
61025554253523504434
732113453110662314
oct3101000701502246
9472483758266664
10110020000122022
1132068246942961
121040a74352811a
134950ac29bc7a3
141d24dd42590b4
15cabd154a4a17
hex6410070684a6

110020000122022 has 8 divisors (see below), whose sum is σ = 168541276782816. Its totient is φ = 53839574527752.

The previous prime is 110020000122013. The next prime is 110020000122023. The reversal of 110020000122022 is 220221000020011.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 110020000121993 and 110020000122011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110020000122023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 585212766513 + ... + 585212766700.

It is an arithmetic number, because the mean of its divisors is an integer number (21067659597852).

Almost surely, 2110020000122022 is an apocalyptic number.

110020000122022 is a deficient number, since it is larger than the sum of its proper divisors (58521276660794).

110020000122022 is a wasteful number, since it uses less digits than its factorization.

110020000122022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1170425533262.

The product of its (nonzero) digits is 32, while the sum is 13.

Adding to 110020000122022 its reverse (220221000020011), we get a palindrome (330241000142033).

The spelling of 110020000122022 in words is "one hundred ten trillion, twenty billion, one hundred twenty-two thousand, twenty-two".

Divisors: 1 2 47 94 1170425533213 2340851066426 55010000061011 110020000122022