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1100200120223 is a prime number
BaseRepresentation
bin10000000000101001000…
…010011000111110011111
310220011210211121221001212
4100000221002120332133
5121011202212321343
62201231442455035
7142325661502301
oct20005102307637
93804724557055
101100200120223
11394657316306
1215928696447b
137c9963a51c9
143b36dcbb971
151d943330c18
hex10029098f9f

1100200120223 has 2 divisors, whose sum is σ = 1100200120224. Its totient is φ = 1100200120222.

The previous prime is 1100200120189. The next prime is 1100200120231. The reversal of 1100200120223 is 3220210020011.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1100200120223 - 240 = 688492447 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100200120198 and 1100200120207.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100200140223) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100060111 + 550100060112.

It is an arithmetic number, because the mean of its divisors is an integer number (550100060112).

Almost surely, 21100200120223 is an apocalyptic number.

1100200120223 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100200120223 is an equidigital number, since it uses as much as digits as its factorization.

1100200120223 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 1100200120223 its reverse (3220210020011), we get a palindrome (4320410140234).

The spelling of 1100200120223 in words is "one trillion, one hundred billion, two hundred million, one hundred twenty thousand, two hundred twenty-three".