1100201303221 has 4 divisors (see below), whose sum is σ = 1103371912512. Its totient is φ = 1097030693932.

The previous prime is 1100201303167. The next prime is 1100201303237. The reversal of 1100201303221 is 1223031020011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100201303221 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100201303195 and 1100201303204.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100201303281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1585304125 + ... + 1585304818.

It is an arithmetic number, because the mean of its divisors is an integer number (275842978128).

Almost surely, 2^{1100201303221} is an apocalyptic number.

It is an amenable number.

1100201303221 is a deficient number, since it is larger than the sum of its proper divisors (3170609291).

1100201303221 is an equidigital number, since it uses as much as digits as its factorization.

1100201303221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3170609290.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1100201303221 its reverse (1223031020011), we get a palindrome (2323232323232).

The spelling of 1100201303221 in words is "one trillion, one hundred billion, two hundred one million, three hundred three thousand, two hundred twenty-one".