Base | Representation |
---|---|
bin | 10100011111100010… |
… | …11011001111111111 |
3 | 1001101202021012012022 |
4 | 22033301123033333 |
5 | 140013010030101 |
6 | 5015415430355 |
7 | 536432511254 |
oct | 121761331777 |
9 | 31352235168 |
10 | 11002033151 |
11 | 47363a738a |
12 | 21706853bb |
13 | 1064489bb5 |
14 | 76527d42b |
15 | 445d41a1b |
hex | 28fc5b3ff |
11002033151 has 2 divisors, whose sum is σ = 11002033152. Its totient is φ = 11002033150.
The previous prime is 11002033103. The next prime is 11002033171. The reversal of 11002033151 is 15133020011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11002033151 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11002033171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501016575 + 5501016576.
It is an arithmetic number, because the mean of its divisors is an integer number (5501016576).
Almost surely, 211002033151 is an apocalyptic number.
11002033151 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002033151 is an equidigital number, since it uses as much as digits as its factorization.
11002033151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 90, while the sum is 17.
Adding to 11002033151 its reverse (15133020011), we get a palindrome (26135053162).
The spelling of 11002033151 in words is "eleven billion, two million, thirty-three thousand, one hundred fifty-one".
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