| Base | Representation |
|---|---|
| bin | 10100011111100011… |
| … | …01110000000111100 |
| 3 | 1001101202102002122000 |
| 4 | 22033301232000330 |
| 5 | 140013020010022 |
| 6 | 5015421222300 |
| 7 | 536433251325 |
| oct | 121761560074 |
| 9 | 31352362560 |
| 10 | 11002110012 |
| 11 | 473644a103 |
| 12 | 2170701990 |
| 13 | 10644b5b8a |
| 14 | 76529d44c |
| 15 | 445d596ac |
| hex | 28fc6e03c |
11002110012 has 48 divisors (see below), whose sum is σ = 28529642400. Its totient is φ = 3666643200.
The previous prime is 11002110011. The next prime is 11002110029. The reversal of 11002110012 is 21001120011.
It is a happy number.
11002110012 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 11002109976 and 11002110003.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11002110011) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1064164 + ... + 1074452.
It is an arithmetic number, because the mean of its divisors is an integer number (594367550).
Almost surely, 211002110012 is an apocalyptic number.
11002110012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
11002110012 is an abundant number, since it is smaller than the sum of its proper divisors (17527532388).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11002110012 is a wasteful number, since it uses less digits than its factorization.
11002110012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20203 (or 20195 counting only the distinct ones).
The product of its (nonzero) digits is 4, while the sum is 9.
Adding to 11002110012 its reverse (21001120011), we get a palindrome (32003230023).
Subtracting 11002110012 from its reverse (21001120011), we obtain a palindrome (9999009999).
It can be divided in two parts, 1100 and 2110012, that added together give a palindrome (2111112).
The spelling of 11002110012 in words is "eleven billion, two million, one hundred ten thousand, twelve".
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