Base | Representation |
---|---|
bin | 110011001110111000… |
… | …1111111101001111111 |
3 | 101111222120111200201012 |
4 | 1212131301333221333 |
5 | 3300310423423403 |
6 | 122313150305435 |
7 | 10643300466644 |
oct | 1463561775177 |
9 | 344876450635 |
10 | 110021311103 |
11 | 427291864a0 |
12 | 193a5ab827b |
13 | a4b4a4c022 |
14 | 5479d6ddcb |
15 | 2cdde06ed8 |
hex | 199dc7fa7f |
110021311103 has 4 divisors (see below), whose sum is σ = 120023248488. Its totient is φ = 100019373720.
The previous prime is 110021311091. The next prime is 110021311117. The reversal of 110021311103 is 301113120011.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 110021311103 - 24 = 110021311087 is a prime.
It is a super-2 number, since 2×1100213111032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110021311303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000968676 + ... + 5000968697.
It is an arithmetic number, because the mean of its divisors is an integer number (30005812122).
Almost surely, 2110021311103 is an apocalyptic number.
110021311103 is a deficient number, since it is larger than the sum of its proper divisors (10001937385).
110021311103 is a wasteful number, since it uses less digits than its factorization.
110021311103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10001937384.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 110021311103 its reverse (301113120011), we get a palindrome (411134431114).
It can be divided in two parts, 110021 and 311103, that added together give a palindrome (421124).
The spelling of 110021311103 in words is "one hundred ten billion, twenty-one million, three hundred eleven thousand, one hundred three".
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