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1100213143 = 10381113171
BaseRepresentation
bin100000110010011…
…1110101110010111
32211200020121200221
41001210332232113
54223123310033
6301101215211
736156441331
oct10144765627
92750217627
101100213143
11515050467
12268561507
13146c269c3
14a6196451
15668c912d
hex4193eb97

1100213143 has 8 divisors (see below), whose sum is σ = 1112349056. Its totient is φ = 1088105400.

The previous prime is 1100213131. The next prime is 1100213159. The reversal of 1100213143 is 3413120011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1100213143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100213243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76948 + ... + 90118.

It is an arithmetic number, because the mean of its divisors is an integer number (139043632).

Almost surely, 21100213143 is an apocalyptic number.

1100213143 is a deficient number, since it is larger than the sum of its proper divisors (12135913).

1100213143 is a wasteful number, since it uses less digits than its factorization.

1100213143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14085.

The product of its (nonzero) digits is 72, while the sum is 16.

The square root of 1100213143 is about 33169.4609995399. The cubic root of 1100213143 is about 1032.3467848719.

Adding to 1100213143 its reverse (3413120011), we get a palindrome (4513333154).

The spelling of 1100213143 in words is "one billion, one hundred million, two hundred thirteen thousand, one hundred forty-three".

Divisors: 1 103 811 13171 83533 1356613 10681681 1100213143