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110022143407 = 1154919182123
BaseRepresentation
bin110011001110111010…
…1001010110110101111
3101111222122001222102021
41212131311022312233
53300311132042112
6122313220211011
710643310534331
oct1463565126657
9344878058367
10110022143407
11427296a4850
12193a6239a67
13a4b4c80b07
14547a109451
152cde01d907
hex199dd4adaf

110022143407 has 8 divisors (see below), whose sum is σ = 120027000960. Its totient is φ = 100017759960.

The previous prime is 110022143393. The next prime is 110022143459. The reversal of 110022143407 is 704341220011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 110022143407 - 219 = 110021619119 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110022143477) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 513048 + ... + 695170.

It is an arithmetic number, because the mean of its divisors is an integer number (15003375120).

Almost surely, 2110022143407 is an apocalyptic number.

110022143407 is a deficient number, since it is larger than the sum of its proper divisors (10004857553).

110022143407 is a wasteful number, since it uses less digits than its factorization.

110022143407 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 237053.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 110022143407 its reverse (704341220011), we get a palindrome (814363363418).

The spelling of 110022143407 in words is "one hundred ten billion, twenty-two million, one hundred forty-three thousand, four hundred seven".

Divisors: 1 11 54919 182123 604109 2003353 10002013037 110022143407