1100240133 has 4 divisors (see below), whose sum is σ = 1466986848. Its totient is φ = 733493420.

The previous prime is 1100240123. The next prime is 1100240149. The reversal of 1100240133 is 3310420011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 3310420011 = 3 ⋅1103473337.

It is a cyclic number.

It is not a de Polignac number, because 1100240133 - 2⁵ = 1100240101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100240123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 183373353 + ... + 183373358.

It is an arithmetic number, because the mean of its divisors is an integer number (366746712).

Almost surely, 2^1100240133 is an apocalyptic number.

It is an amenable number.

1100240133 is a deficient number, since it is larger than the sum of its proper divisors (366746715).

1100240133 is an equidigital number, since it uses as much as digits as its factorization.

1100240133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 366746714.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 1100240133 is about 33169.8678471893. The cubic root of 1100240133 is about 1032.3552265125.

Adding to 1100240133 its reverse (3310420011), we get a palindrome (4410660144).

The spelling of 1100240133 in words is "one billion, one hundred million, two hundred forty thousand, one hundred thirty-three".