11003100103 has 4 divisors (see below), whose sum is σ = 11358038848. Its totient is φ = 10648161360.

The previous prime is 11003100079. The next prime is 11003100113. The reversal of 11003100103 is 30100130011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11003100103 is a prime.

It is a super-2 number, since 2×11003100103² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 11003100103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11003100113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 177469326 + ... + 177469387.

It is an arithmetic number, because the mean of its divisors is an integer number (2839509712).

Almost surely, 2^11003100103 is an apocalyptic number.

11003100103 is a deficient number, since it is larger than the sum of its proper divisors (354938745).

11003100103 is an equidigital number, since it uses as much as digits as its factorization.

11003100103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 354938744.

The product of its (nonzero) digits is 9, while the sum is 10.

Adding to 11003100103 its reverse (30100130011), we get a palindrome (41103230114).

The spelling of 11003100103 in words is "eleven billion, three million, one hundred thousand, one hundred three".