11003100113 has 2 divisors, whose sum is σ = 11003100114. Its totient is φ = 11003100112.

The previous prime is 11003100079. The next prime is 11003100137. The reversal of 11003100113 is 31100130011.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8323277824 + 2679822289 = 91232^2 + 51767^2 .

It is a cyclic number.

It is not a de Polignac number, because 11003100113 - 2⁶ = 11003100049 is a prime.

It is a super-2 number, since 2×11003100113² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11003100094 and 11003100103.

It is not a weakly prime, because it can be changed into another prime (11003100313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501550056 + 5501550057.

It is an arithmetic number, because the mean of its divisors is an integer number (5501550057).

Almost surely, 2^11003100113 is an apocalyptic number.

It is an amenable number.

11003100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11003100113 is an equidigital number, since it uses as much as digits as its factorization.

11003100113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9, while the sum is 11.

Adding to 11003100113 its reverse (31100130011), we get a palindrome (42103230124).

The spelling of 11003100113 in words is "eleven billion, three million, one hundred thousand, one hundred thirteen".