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110031202102 = 255015601051
BaseRepresentation
bin110011001111001011…
…1101110011100110110
3101112000021010012121111
41212132113232130312
53300320441431402
6122314142305234
710643450533453
oct1463627563466
9345007105544
10110031202102
1142733821778
12193a928821a
13a4b6b030a3
14547b3c682a
152cdec0c9d7
hex199e5ee736

110031202102 has 4 divisors (see below), whose sum is σ = 165046803156. Its totient is φ = 55015601050.

The previous prime is 110031202097. The next prime is 110031202123. The reversal of 110031202102 is 201202130011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 201202130011 = 972074248763.

It is a super-2 number, since 2×1100312021022 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27507800524 + ... + 27507800527.

It is an arithmetic number, because the mean of its divisors is an integer number (41261700789).

Almost surely, 2110031202102 is an apocalyptic number.

110031202102 is a deficient number, since it is larger than the sum of its proper divisors (55015601054).

110031202102 is an equidigital number, since it uses as much as digits as its factorization.

110031202102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55015601053.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 110031202102 its reverse (201202130011), we get a palindrome (311233332113).

The spelling of 110031202102 in words is "one hundred ten billion, thirty-one million, two hundred two thousand, one hundred two".

Divisors: 1 2 55015601051 110031202102