1100320002013 has 2 divisors, whose sum is σ = 1100320002014. Its totient is φ = 1100320002012.

The previous prime is 1100320002011. The next prime is 1100320002043. The reversal of 1100320002013 is 3102000230011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1055544595609 + 44775406404 = 1027397^2 + 211602^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100320002013 - 2¹ = 1100320002011 is a prime.

Together with 1100320002011, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 1100320001984 and 1100320002002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100320002011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550160001006 + 550160001007.

It is an arithmetic number, because the mean of its divisors is an integer number (550160001007).

Almost surely, 2^{1100320002013} is an apocalyptic number.

It is an amenable number.

1100320002013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100320002013 is an equidigital number, since it uses as much as digits as its factorization.

1100320002013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 1100320002013 its reverse (3102000230011), we get a palindrome (4202320232024).

The spelling of 1100320002013 in words is "one trillion, one hundred billion, three hundred twenty million, two thousand, thirteen".