11003201220023 has 4 divisors (see below), whose sum is σ = 11004112621248. Its totient is φ = 11002289818800.

The previous prime is 11003201220001. The next prime is 11003201220059. The reversal of 11003201220023 is 32002210230011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11003201220023 - 2²⁶ = 11003134111159 is a prime.

It is a super-2 number, since 2×11003201220023² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11003201219983 and 11003201220010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11003207220023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 455682503 + ... + 455706648.

It is an arithmetic number, because the mean of its divisors is an integer number (2751028155312).

Almost surely, 2^{11003201220023} is an apocalyptic number.

11003201220023 is a deficient number, since it is larger than the sum of its proper divisors (911401225).

11003201220023 is an equidigital number, since it uses as much as digits as its factorization.

11003201220023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 911401224.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 11003201220023 its reverse (32002210230011), we get a palindrome (43005411450034).

The spelling of 11003201220023 in words is "eleven trillion, three billion, two hundred one million, two hundred twenty thousand, twenty-three".