Base | Representation |
---|---|
bin | 10000000000110000110… |
… | …010001111101001101111 |
3 | 10220012010220012212021201 |
4 | 100000300302033221233 |
5 | 121011434001333310 |
6 | 2201252404510331 |
7 | 142332130402060 |
oct | 20006062175157 |
9 | 3805126185251 |
10 | 1100330105455 |
11 | 394713728119 |
12 | 1593023ab3a7 |
13 | 7c9b72b7049 |
14 | 3b383276567 |
15 | 1d94e959e3a |
hex | 10030c8fa6f |
1100330105455 has 8 divisors (see below), whose sum is σ = 1509024144672. Its totient is φ = 754512072288.
The previous prime is 1100330105411. The next prime is 1100330105467. The reversal of 1100330105455 is 5545010330011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1100330105455 - 27 = 1100330105327 is a prime.
It is a super-2 number, since 2×11003301054552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15719001472 + ... + 15719001541.
It is an arithmetic number, because the mean of its divisors is an integer number (188628018084).
Almost surely, 21100330105455 is an apocalyptic number.
1100330105455 is a deficient number, since it is larger than the sum of its proper divisors (408694039217).
1100330105455 is an equidigital number, since it uses as much as digits as its factorization.
1100330105455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31438003025.
The product of its (nonzero) digits is 4500, while the sum is 28.
Adding to 1100330105455 its reverse (5545010330011), we get a palindrome (6645340435466).
The spelling of 1100330105455 in words is "one trillion, one hundred billion, three hundred thirty million, one hundred five thousand, four hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •