Base | Representation |
---|---|
bin | 10100011111110010… |
… | …11110001011011101 |
3 | 1001101220020100101222 |
4 | 22033321132023131 |
5 | 140014030023201 |
6 | 5015532543125 |
7 | 536456444345 |
oct | 121771361335 |
9 | 31356210358 |
10 | 11004142301 |
11 | 4737607a89 |
12 | 2171321aa5 |
13 | 1064a47c09 |
14 | 76566bd25 |
15 | 44610b91b |
hex | 28fe5e2dd |
11004142301 has 2 divisors, whose sum is σ = 11004142302. Its totient is φ = 11004142300.
The previous prime is 11004142283. The next prime is 11004142309. The reversal of 11004142301 is 10324140011.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8315616100 + 2688526201 = 91190^2 + 51851^2 .
It is a cyclic number.
It is not a de Polignac number, because 11004142301 - 218 = 11003880157 is a prime.
It is a super-2 number, since 2×110041423012 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11004142301.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11004142309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5502071150 + 5502071151.
It is an arithmetic number, because the mean of its divisors is an integer number (5502071151).
Almost surely, 211004142301 is an apocalyptic number.
It is an amenable number.
11004142301 is a deficient number, since it is larger than the sum of its proper divisors (1).
11004142301 is an equidigital number, since it uses as much as digits as its factorization.
11004142301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 11004142301 its reverse (10324140011), we get a palindrome (21328282312).
The spelling of 11004142301 in words is "eleven billion, four million, one hundred forty-two thousand, three hundred one".
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