Base | Representation |
---|---|
bin | 11001000010001010101101… |
… | …010111001011101010001111 |
3 | 112102211110121021201212102202 |
4 | 121002022231113023222033 |
5 | 103412340001122413403 |
6 | 1030055142054312115 |
7 | 32122320056265545 |
oct | 3102125527135217 |
9 | 472743537655382 |
10 | 110100100201103 |
11 | 32099210294921 |
12 | 1042217895863b |
13 | 495851979509c |
14 | 1d28c32405d95 |
15 | cade52641688 |
hex | 6422ad5cba8f |
110100100201103 has 2 divisors, whose sum is σ = 110100100201104. Its totient is φ = 110100100201102.
The previous prime is 110100100201057. The next prime is 110100100201111. The reversal of 110100100201103 is 301102001001011.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110100100201103 - 222 = 110100096006799 is a prime.
It is a super-2 number, since 2×1101001002011032 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (110100100203103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55050050100551 + 55050050100552.
It is an arithmetic number, because the mean of its divisors is an integer number (55050050100552).
Almost surely, 2110100100201103 is an apocalyptic number.
110100100201103 is a deficient number, since it is larger than the sum of its proper divisors (1).
110100100201103 is an equidigital number, since it uses as much as digits as its factorization.
110100100201103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6, while the sum is 11.
Adding to 110100100201103 its reverse (301102001001011), we get a palindrome (411202101202114).
The spelling of 110100100201103 in words is "one hundred ten trillion, one hundred billion, one hundred million, two hundred one thousand, one hundred three".
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