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11010011121211 is a prime number
BaseRepresentation
bin1010000000110111011111…
…0011010100011000111011
31102222112202121100022212111
42200031313303110120323
52420342000321334321
635225532420353151
72214306224254534
oct240156763243073
942875677308774
1011010011121211
11356535727a503
1212999925457b7
1361b31650650b
142a0c5cd9168b
151415e05125e1
hexa0377cd463b

11010011121211 has 2 divisors, whose sum is σ = 11010011121212. Its totient is φ = 11010011121210.

The previous prime is 11010011121157. The next prime is 11010011121251. The reversal of 11010011121211 is 11212111001011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11010011121211 - 213 = 11010011113019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11010011121191 and 11010011121200.

It is not a weakly prime, because it can be changed into another prime (11010011121251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5505005560605 + 5505005560606.

It is an arithmetic number, because the mean of its divisors is an integer number (5505005560606).

Almost surely, 211010011121211 is an apocalyptic number.

11010011121211 is a deficient number, since it is larger than the sum of its proper divisors (1).

11010011121211 is an equidigital number, since it uses as much as digits as its factorization.

11010011121211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 13.

Adding to 11010011121211 its reverse (11212111001011), we get a palindrome (22222122122222).

The spelling of 11010011121211 in words is "eleven trillion, ten billion, eleven million, one hundred twenty-one thousand, two hundred eleven".